php - MySQLi prepared insert statement fails -


मैं अपने कोड को mysqli :: के बजाय mysql _ * और मैंने INSERT स्टेटमेंट के साथ एक समस्या में भाग लिया है मेरे पास निम्न कथन है: 

  $ stmt = $ link- & gt; तैयार करें ("तालिका` (`एक`,` बी`, `सी`) मूल्यों (" INSERT INS? ,?) "); $ Stmt- & gt; बाँध_परम ("sss", $ a, $ b, "0"); $ Stmt- & gt; निष्पादित ();   
 मैंने  $ stmt  की जांच की है और यह एक उचित  mysqli_stmt  वस्तु है यह ठीक से तैयार है, लेकिन किसी कारण से, बयान निष्पादित नहीं किया जाएगा।  
  संपादित करें   
 मैंने यह निर्धारित किया है कि मैं अपने सर्वर से एक 500 त्रुटि प्राप्त कर सकता हूं।  
 समस्या  bind_param  विधि से आ रही है।  
  2 संपादित करें   
 ठीक है, इसलिए मुझे दे रही त्रुटि PHP यह है:  
 
 घातक त्रुटि: संदर्भ में पैरामीटर 4 से नहीं जा सकता ...   
 यह बिन्दु_परम की रेखा को इंगित करता है   < P> 
 
 आप bind_param के लिए एक निरंतर पास नहीं कर सकते वैरिएबल में मान पहले डालें:  
  $ status = "0"; $ Stmt- & gt; बाइंड_परम ("sss", $ oid, $ cid, $ status); $ Stmt- & gt; निष्पादित ();

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