regex - Why does Python add extra quotes in my array returned by split()? -


The relevant data is parsed here: 

  Optional classname: 'FutureServ', optional Classname: ['HardwareHarvi'], Alternative ClassName: ['OptimusServe', 'OptimusSwive Two']   
 Here's my Reggae:  
  alternate_regex = re .compile ('. * AlternateClassName \ s *: \ * (\ [* * * * * * * *.]] [\ * \ "] \ * S (*) \ * s [\. ? '\']). * ', Re.m)   
 And here is my code:  
  alternate_match = alternate_regex.match (line) if Alternate_match and alternate_match group Alternate_mackgrup (1): Alternatelist = Alternate_mackgrup (1) Kstrip (). The printed (',') print is alternateList dependent _mapping [classpathTxt] ['alternateList'] = Optional list   
 printed here:  
  [" I was hoping that this would be: 'futurus'' '[] ["hardware service"] ["[' optism savour ',' 'optimusvers'' ']]   
  
  ['FutureSwarvi'] ['Hardware servi'] ['Optimism Servi', 'Optimus All Two']   
 Anyone know that What is happening?   
 
 
 You are not doing anything because there is no parameter in it. Instead, call it  .strip ("'")   
 >> gt; & Gt; X = "Hello" "& gt; & Gt; & Gt; X.strip () "Hello" "& gt; & Gt; & Gt; X.strip ("'")' Hello '& gt; & Gt; & Gt;

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