regex - VIM: Replace function call without the arguments -

How do I search for a function call, but how can I do without the arguments of the function?

to foobar: arg1, arg2;

My goal is to search and replace the foobar (arg1, arg2) to keep I> Arg1, arg2 .

How do I solve it? Is there any best practice?

Try it out:

Insert a row at the top of the file - We will write a macro here (this letter is not O, zero).

  ggO   
 followed by an open bracket for a string of word-letters Instructions to do, and  
  / \ w * (/ e>  & lt; Ctrl-M & gt;   < P> Then we leave the cursor at the end of the match, go to the mailing bracket and replace it with a semicolon     
 Other Back to the Front (ctrl-letter o then, :      
 This field will be from  Change:   
  P> 
  s:  gt; & lt; Ctrl-V & gt; & lt; Esc & gt; < / Code>  
 then perform this macro again (it is assumed that it is  q  register  
  @q   
 Our macro is done, exhaust insert mode (should read your line:  / \ w * (/ a ^ m% r; ^ OS: ^ [[[@ q]  now)  
  & lt; Esc & gt;   
 Drag the line  q  register (which also removes it from the current file, sends back its file. Finally, Big moment: Created by us Execute recursive macro  @     
 / Code> register, which will replace the entire file.  
  @q   BENEFITS : This handles nested functions properly, because it is not relying on those regular expressions, who have brackets Instead, we rely on %  to match the parentheses.  
 Demo:  
  foo (Bar, baz) foo (foo (bar), foo (foo, foo, foo)) foo (bar (baz ()))   
    < P>  Edit : Typo ( \ w , not in search  \ e ).