Validating user fed time in bash with regex pattern -


इस सवाल का पहले से ही एक उत्तर है: < 6 उत्तर

एक उपयोगकर्ता को खिलाया समय मान: / p> 

  •   read -p "प्रारंभ समय जो आप शुरू करना चाहते हैं (hh: mm: ss)" user_start_time   
     और regex:  
      समयपटल = "[0-2] [0-3]: [0-5] [0-9]: [0-5] [0-9]"   
     अगर मैं ऐसा करता हूं:    
     यह गूंजता है ..... यह न्यूबी होने की पुष्टि नहीं करता है, मैं  int  या  स्ट्रिंग की तुलना समझता हूँ < / कोड> लेकिन हम कैसे  समय  के बारे में जाते हैं ( तिथि भी है, लेकिन  दिनांक -d  बहुत सी समस्याएं हल करता है )  < P> लेकिन स्वीकार किए गए उत्तर को समझ नहीं सका!   
     
     
     के लिए Regex मिलान करने के लिए आपको  = ~  ऑपरेटर के बजाय  ==  का उपयोग करने की आवश्यकता है BASH में तो इसे इस तरह का उपयोग करें:  
      [["$ user_start_time" = ~ $ timePattern]] & amp; amp; गूंज "in if" || इसके अलावा आपको regex variable  $ timePattern     के आसपास उद्धरणों को हटाने की आवश्यकता है।

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