java - Spring bean instantiation by passing constructor args? -


इस सवाल का पहले से ही एक उत्तर है: < / P>

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    मेरे पास वसंत सेम नीचे है। 

      सार्वजनिक वर्ग कर्मचारी 2 {निजी इंट आईडी; निजी स्ट्रिंग का नाम; निजी डबल वेतन; सार्वजनिक कर्मचारी 2 (इंट आईडी, स्ट्रिंग का नाम, डबल वेतन) {this.id = id; This.name = name; इस.salary = वेतन;   
     अब मैं स्प्रिंग कॉन्फ़िगरेशन फ़ाइल में कॉन्फ़िग के नीचे है।  
      & lt; bean id = "emp2 "वर्ग =" com.basic.Employee2 "& gt; & Lt; constructor-arg नाम = "id" मान = "" / & gt; & Lt; constructor-arg नाम = "नाम" मान = "" / & gt; & Lt; कन्स्ट्रक्टर- आर्ग नाम = "वेतन" मान = "" / & gt; & Lt; / सेम ​​& gt;   
     अब मैं गतिशील कोड से ऊपर के रूप में मानों को नहीं मान सकता।  
     अब मैं स्प्रिंग बीन प्रोग्रामाइम नीचे कोड का उपयोग कर रहा हूं।  बीन स्कोप सिंगलटन  है।  
      कर्मचारी 2 एएमपी = (कर्मचारी 2) applicationContext.getBean ("emp2");   
       
       
     Div class = "post-text" itemprop = "text"> 
     आप विधि का उपयोग कर सकते हैं, जो  
     
     स्पष्ट कन्स्ट्रक्टर तर्क / फ़ैक्टरी विधि तर्क निर्दिष्ट करने देता है, निर्दिष्ट डिफ़ॉल्ट तर्क को ओवरराइड करता है (यदि कोई है) बीन की परिभाषा में।   
     उदाहरण के लिए:  
      पूर्णांक param1 = 2; स्ट्रिंग param2 = "test"; डबल परम 3 = 3.4; कर्मचारी 2 एएमपी = (कर्मचारी 2) applicationContext.getBean ("emp2", परम 1, परम 2, परम 3);   
     वैसे भी, जब यह संभवतः काम करेगा, आपको  Spring EL  का उपयोग करने पर विचार करना चाहिए, जैसा कि प्रश्न के तहत एक टिप्पणी में उल्लिखित है।

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