php - How would this SQL join work? -


I have two tables, "users" and "jobs".

User table: User ID Username Password Account Type Forum Name Alias ​​Contact Number Email Address

Jobs table: 

  job job job shop job job job place job date job time job rate post date approved job position by post   
 I display all jobs Want, and user's name from the user table, The contact number and email address, where the Jobs table is "Approved" from the "UserID" user table.   
 
 
 View this query  
  SELECT * FROM Jobs at INNER jobs Include users. Approved Users = User ID

Comments

Post a Comment

Popular posts from this blog

sql - Return Function using Cursor -

My current schedule is: USERID Department NAME Real Estimated 522 Xyz Department John Wayne 2/1/14/14 8:34 522 Investigation Department John Wayne 2/17/1411: 21 78 9Except Department Bill Smith 2/17/14 9:41 78 9 Excise Department Bill Smith 2/17/14 11:16 78 9 Excise Department Bill Smith 2 / 17/14 11:50 78 9 Excise Department Bill Smith 2/17/14 12: 18 856 Explore Department Raul Castill 2/17/14 9:25 I have to create a function which enables me to enter a user ID and that Allows the user to return data from the person. However, I want to take the first line and want to hold the actual date and then put it in the 'column' check and I also carry the last row and store it in 'Check Out' in the column call. Basically, for every day, I want to record the records in the user's time and want to take the time for each day. This is what I have done so far " return @RtnValue table (useridd integer, deptname varchar (max), emplname varchar (100), actualDate da...
Read more

javascript - Is there any way to add a new parameter to a function programmatically? -

Since I can set the number of expectations by calling a function its function.length Property, do I have to programmatically create the right number of parameters to include in that function at runtime? Example: var xyz = function (a, b) {}; Var BCD = function (A, B, C, D, E, F) {}; // vararg example var doc = document, func_length = xyz.length; Doc.xyz = (function () {returns function (A, B, C, D, E) works for one / but other is not}}}. Call (doctor); / * With `only two parameters ', like' Return function (A, B)`, if this function is used for `xyz` (although in this case 5 works fine), and return function ( If the function is used for 'BCD' (which does not work with only five parameters) with A, B, C, D, E, F) `6 / / Xyz.apply (blank, arguments) Think about ... but which logic ..? : // Returning function (A, B, C, D, E) does not support work with more than five parameters, which will be mostly class - hence my question / I also know very well That I use an obj...
Read more

sql server - How to use pivot in this table -

वास्तविक तालिका संरचना ==================== =============== slno ParnetID ParnetName संवर्धन मार्केटर 1 SLM1010S SKR.RAJASHEGARAN 2 43640 2 40049 M.KANNAN 3 43640 3 40018 M.PRABU 6 43,640 4 SLM1010S SKR.RAJASHEGARAN 2 43641 5 40042 M.KANNAN 3 43,641 6 40011 M.PRABU 6 43,641 मैं अपने प्रश्न हैं: अस्थायी रूप (slno, parentid, parentname, parentpromotionid, marketerid, (चयन गणना (*) parentmaster कहां t1.marketerid = marketerid और t1.parentid से चयन युक्त = parentid और t1.parentname = parentname और slno & lt; = t1.slno) ROWNUM के रूप में parentmaster t1 रूप से) का चयन करें marketerid, [2], [6], [3] अस्थायी धुरी से (न्यूनतम (parentid) के लिए parentpromotionid में ( [2], [6], [3])) के रूप में टी लेकिन मैं इस तालिका संरचना चाहते हैं MarketerID 2 से 6 3 43,640 SLM1010S 40,018 40049 43641 SLM1010S 40011 40042 यह आपकी मदद कर सकता है .. बाज़ार का चयन करें, [2], [3], [6] से ( मार्केटर का चयन करें, संवर्धन, ParnetID parentmaster) घ धुरी (न्यूनतम (ParnetID) ([2], [3], [6])) के ...
Read more