Scala regex format match result -


मैंने एक फ़ंक्शन लिखा 

  def extract मोबाइल नंबर: सूची [स्ट्रिंग] = {pattern.findAllIn (एस) .toList}   
 जहां  
  वैल पैटर्न = "[0- 9] {9}"। R   <पी> जो सूची देता है [इंट] 
 उदा इनपुट "मैडम कृपया मुझे 111111111 पर कॉल करें और 223322 पर लैंडलाइन" आउटपुट: लिस्ट [111111111]  
 चूंकि मैं सीख रहा हूँ, मैं यह समझ नहीं पा रहा हूं कि मैं कैसे पैटर्न का उपयोग कर सकता हूं। ReplaceAllIn (s, matcher) लौटने के लिए "मैडम कृपया मुझे  111-111-111  और 223322 पर लैंडलाइन पर कॉल करें।"   
 
 <पूर्व>  val input =" मैडम कृपया मुझे 111111111 पर कॉल करें और 223322 पर लैंडलाइन ":: नील वेल फोन नंबर =" (। +) ([0- 9] {3}) ([0- 9] {3}) ([0- 9] {3}) (। +) ".आर मूल्य संसाधित = input.map {केस फोन नंबर (उपसर्ग, पी 1, पी 2, पी 3, प्रत्यय) = & gt; S "$ उपसर्ग $ p1- $ p2- $ p3 $ प्रत्यय" केस s = & gt; S} प्रसंस्कृत। फोरेक (println)   
 आउटपुट:  
  मैडम कृपया मुझे 111-111-111 पर कॉल करें और 223322 पर लैंडलाइन कॉल करें  < / प्री>

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