Notice: Undefined index: index.php -


मुझे मिल रहा है

नोटिस: अपरिभाषित सूचकांक: index.php xxxxx / Index.php पंक्ति 26 पर

जब मैं menu.php से $ submenu चर सरणी को निकालता हूं सब कुछ ठीक काम करता है लेकिन जब मैं $ उपमेनू सरणी चर जोड़ता हूं, मुझे त्रुटि संदेश मिलता है I `मैं यहाँ क्या करने की कोशिश कर रहा हूं शीर्ष स्तर को पहले प्राप्त कर रहा है और फिर खोज लें कि क्या उनकी कोई भी बच्चे उपनुमा

Index.php फ़ाइल पर मुझे यह कोड है 

  foreach ($ मेनू $ मेनू के रूप में) {$ title = $ menu [0]; $ मुल्ये = $ मेनू [1]; $ Template = $ मेनू [2]; $ वर्ग = $ मेनू [3]; $ Id = $ मेनू [4]; $ आइकन = $ मेनू [5]; यदि (! $ शीर्षक) {$ title = 'no title';} अगर ($ वर्ग) {$ class = 'class =' ​​'। $ Class।' '' ';} Else {$ class =' ​​';} अगर ( $ Id) {$ id = 'id = "'। $ Id। '' ';} Else {$ id =' ';} अगर (! $ आइकन) {$ icon =" menu-default.png ";} गूंज '& Lt; a href = "'। $ टेम्प्लेट। '' '। $ वर्ग।' '। $ आईडी।' & Gt; ' । $ शीर्षक '& Lt; / a & gt;' । "& Lt; br / & gt;"; / * लाइन 26 यहां शुरू होता है / / ($ उपमेन्यू [$ टेम्प्लेट]) {विदेशी उपनाम ($ उपमेन्यू [$ टेम्प्लेट] $ उपमेनू के रूप में) {गूंज '& lt; a href = "#" & gt;' । $ उपमेन्यू [0] '& Lt; / a & gt;' । "& Lt; br / & gt;"; }}}   
 मेनू.php फ़ाइल पर  
  $ मेनू [1] = सरणी ('डैशबोर्ड', '0', 'index.php' , 'साइडबार-मेनू', '', 'मेनू-डैशबोर्ड'); $ मेनू [2] = सरणी ('पृष्ठ', '0', 'pages.php', 'साइडबार-मेनू', '', 'मेनू-डैशबोर्ड'); $ मेनू [3] = सरणी ('मीडिया', '0', 'media.php', 'साइडबार-मेनू', '', 'मेनू-डैशबोर्ड'); $ मेनू [4] = सरणी ('उपकरण', '0', 'tools.php', 'sidebar-menu', '', 'menu-dashboard'); $ मेनू [5] = सरणी ('उपयोगकर्ता', '0', 'users.php', 'sidebar-menu', '', 'menu-dashboard'); $ मेनू [6] = सरणी ('सेटिंग्स', '0', 'settings.php', 'sidebar-menu', '', 'menu-dashboard'); $ सबमेनू ['pages.php'] [1] = सरणी ('सभी लिंक 1', 'व्यवस्थापक-मेनू', 'प्रबंधन_लिंक', 'लिंक-प्रबंधक.एफ़पी'); $ उपमेनु ['pages.php'] [2] = सरणी ('सभी लिंक 2', 'व्यवस्थापक-मेनू', 'प्रबंधन_लिंक', 'लिंक-प्रबंधक.एफ़पी'); $ उपमेन्यू ['pages.php'] [3] = सरणी ('सभी लिंक 3', 'व्यवस्थापक-मेनू', 'प्रबंधन_लिंक', 'लिंक-प्रबंधक.एफ़पी'); $ उपमेनु ['pages.php'] [4] = सरणी ('सभी लिंक 4', 'व्यवस्थापक-मेनू', 'प्रबंधन_लिंक', 'लिंक-प्रबंधक.एफ़पी');    
 
 
 इसके बजाय  
  यदि ($ उपमेन्यू [ $ टेम्प्लेट]) {  
 उपयोग  
  यदि (! खाली ($ उपमेन्यू [$ टेम्प्लेट])) {  < P> यह तब ही ट्रिगर करेगा जब $ submenu [$ template] मौजूद है और खाली नहीं है

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