Typed Function and Currying in Scala -


In Scala, I have such a function: 

  def foo [R] ] (X: string, y: () => R):   
 then I can:  
  val something: int = foo ("Bar", {() => 13})   
 Is there any way to use function curry without "losing" the type of second argument?  ; nothing) Some Val: int = bar ((=) 13)    
 
 
  case class foo (x: string) AnyVal {def apply [r] (y: (=);): r = y ()} val bar = foo ("bar") Val some: int = Bar ((=) = 13) // int = 13

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