c# - Getting the fully qualified name of a type from a TypeInfo object -
After
In any way to get a fully qualified name of the type contained in a Many of these values in the debugger are shown as well as Note that this should work for every type, so I can not just add a namespace with the name Optional:. Is there another (more favorable) way to get the exact type? For reference: I want to see that there are certain methods in the type-parameter of the class. Therefore my approach was to be the parameter from Due to the reason "integer" your getting keyword is default format TypeInfo object possible?
System.Int32 , but when it is printed, in one of them it is completely Not a valid name. I need to provide a code for
Type.GetType () .
var type INFO = moneycontrol Model Gate type info (logic); Var w = typeInfo.ToString (); // Microsoft.CodeAnalysis.TypeInfo var y = typeInfo.Type.ToString (); // int var z = typeInfo.Type.ToDisplayString (); // int var a = typeInfo.Type.OriginalDefinition.ToDisplayString (); // int var b = typeInfo.Type.OriginalDefinition.ToString (); // int var c = typeInfo.Type.Name; // Int32 var d = typeInfo.Type.MetadataName; // Int32 var e = typeInfo.Type.ToDisplayParts (); // {int} var f = typeInfo.Type.ContainingNamespace; // system
TypeArgumentListSyntax and to get the
TypeInfo from each
TypeSyntax object.
ToDisplayString method is a "format" object that has a nearby feature Gives a great number of options to control how you want to format the stuff:
symbolDisplayFormat = new symbolDisplayFormat (typeQualificationStyle: SymbolDisplayTypeQualificationStyle.NameAndContainingTypesAndNamespaces); String Fully Qualified Name = Typing Simbol Two display string (symbol display format);
SymbolDisplayMiscellaneousOptions.UseSpecialTypes is the flag specified for using the language for special type vs. Does the keywords have regular names?
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