c - Converting characters to hexadecimal -

I'm trying to change a cipher (AES encryption) in hexadecimal values.

I am using the following code (state Sifrtekst) for conversion:

  foreach (char * V, state) {printf ( "% 02X", * V); }   
 For this cipher:  
  '4 ayen w [â ?? ¢ úà ?? J $ one ?? ¶U6   
 I get this output:  
  2734FFFFFFA5575BFFFFFF99FFFFFFFAFFFFFFCB6A240BFFFFFFD318FFFFFFB65536   
 Who correct hex for this cipher is not. I tried other conversion methods, which all took for the same result. In  
 Edit: foreach code:  
  # foreach (item Put array) to \ (int = 1, \ count = 0, \ size = sizeof (array ) / Sizeof * (array); \ keep & count! = Size; \ keep =! Keep, Calculate ++) \ for (item = (array) + count; keep; keep =! Keep)    
 
 
 It is not C, there is no  foreach  in C. It may be C ++, in that case the problem is that the  printf ()  of the % x  conversion specification is being reason-being expanded. There is a signed  char  type on the probability of your platform. Cast the value to  
  Unsigned four .