regex - Find pattern in line and replace where portion of pattern is evaluated in substitution -

I have a text line (new file format with bootstrap values) which has several numbers between 0.000 and 1.000 I want to multiply between 100 and 0 and 100 return values ​​as a rounded integer. These numbers are all before "" and after that ":" There are other numbers in the line of text that I want to leave untouched, which are not surrounded by them. I'm trying to do it with Pearl One-liner:

  perl -ape / s) (\ d \. \ D +): / \) int ($ 1 * 100 + .5): / e.g. Test.newick   
 However, due to a syntax error it is failing, I believe because it is  ")"  and  ":"  Try to stay Any suggestions how can I do this? Thanks!   
 
 
 Some issues:  
 
 A bracket is a regex special character.  
 Your RHS needs to use string combinations, as it is being removed  
 using Consider         
 'S { \] (\ D. \ D +):} {"}" .inte ($ 1 * 100 + .5) ":"} For example 'test.newick'   
 Alternatively, you can use letterhead And if you do not want to duplicate textual text in RHS, then   pre>  perl -ape 's {\) \ K (\ d. \ D +) (? = :)} {Int ($ 1 * 100 + .5)} Example 'test.newick