mysql - Now in UNIX time -


इस सवाल का पहले से ही एक उत्तर है: < / P>

  • 4 जवाब

    मैंने दिनांक फ़ील्ड को बदल दिया है मैं अपनी एक साइट में उपयोग कर रहा हूं नया फ़ील्ड यूनिक्स समय प्रारूप में तिथियों को संग्रहीत करने के लिए प्रतीत होता है।

    मैं इसका उपयोग कर रहा था: 

      और मैट्रिक्स.col_id_3 & gt; (DATE_FORMAT (NOW (), '% Y% m% d'))   
     यह जांचने के लिए कि क्या matrix.col_id_3 में संग्रहीत तिथि आज की तारीख से अधिक थी।  
     मैं UNIX समय प्रारूप के साथ यह कैसे कर सकता हूं?  
     दिनांक इस तरह दिखते हैं: 1412736180   
     
     
     कोशिश करें  
      DATE_FORMAT (FROM_UNIXTIME (मैट्रिक्स.col_id_r), '% Y% m% d') & gt; DATE_FORMAT (NOW (), '% Y% m% d');

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